Course Solutions Uncategorized (Answered) : For a given item, the upper specification limit is 76 and the lower specification limit is 45. We can assume that the process me

(Answered) : For a given item, the upper specification limit is 76 and the lower specification limit is 45. We can assume that the process me

For a given item, the upper specification limit is 76 and the lower specification limit is 45. We can assume that the process mean is centered within this interval. If this process, to be considered capable, must have a Cp of at least 1.4, what is the maximum value for the process standard deviation that would be acceptable?

Expert Answer


cp=1.4

lsl=36

usl=75

we knows that the process capability cp =(usl – lsl)/ 6 s

where s is the standard deviation

=> s = (usl – lsl)/ 6 cp

= (75-36) / ( 6 * 1.4)

= 4.64

hence the maximum value of the standard deviation possible

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