Use the process information provided in the following table,when the sequence of flow is A → B (any machine can be used ifavailable) → C → D (any machine can be used if available).
OperationNumber of Units of EquipmentDesign Capacity
(by equipment)Planned Utilization
(overall)A1215units/hr75.0%B4155, 145, 185,13570.0%C1210units/hr80.0%D2115, 23573.0%
Calculate the maximum (design) capacity and effective capacity.
Expert Answer
Operation
Number of Units of Equipment
Design Capacity
(by equipment)
Planned Utilization
(overall)
Overall Design Capacity
Overall Efficiency Capacity
A
1
215 units/hr
75.0%
215
215*0.75 =161.25
B
4
155, 145, 185, 135
70.0%
155+145+185+135=620
620*0.7 =434
C
1
210 units/hr
80.0%
210
210*0.8=168
D
2
115, 235
73.0%
115+235=350
350*0.73=255.5
From the table,
maximum (design) capacity =434
effective capacity=168