Table 1 Agronomist Wants Compare Crop Yield 3 Varieties Chickpea Seeds Plants 15 Fields 5 Q34295125

TABLE 1

An agronomist wants to compare the crop yield of 3varieties of chickpea seeds. She plants 15 fields, 5 with eachvariety. She then measures the crop yield in bushels per acre.Treating this as a completely randomized design, the results arepresented in the table that follows.

Trial

Smith

Walsh

Trevor

1

11.1

19.0

14.6

2

13.5

18.0

15.7

3

15.3

19.8

16.8

4

14.6

19.6

16.7

5

9.8

16.6

15.2

1. Referring to table 1, the agronomist decided to performan ANOVA F test. The amount of total variation or SST is_____.

1. 82.39

2. 114.82

3. 32.43

4. 41.19

Expert Answer

CM ( correction of mean) = [sigma ( X)]2 / N =(236.3)2 /15 = 3722.51

SST = Sigma ( TCM) – CM = 3804.89 -3722.51 = 82.37

Option 1 is the most appropriate

Table

VarietyDataSumNAvgTCM = (SUM)^2 /NSigma (