A system has an operating time of 10,000 hours. Its MTBF is 250hours. For each corrective maintenance, two technicians have beenassigned. The Mean Corrective Maintenance Time is 2 hours. a)Calculate the number (quantity) of corrective maintenance actions.b) Calculate MLH/OH (Maintenance Labor Hour per Operating Hour)
Expert Answer
T = 10000 hours
MTBF = 250 hours
λ (failure rate) = number of failures/T
MTBF=1/ λ
λ = 1/ 250 = 0.004
Number of failures or corrective actions required = 0.004 *10000 = 40
Total maintenance labor hours = Mean corrective maintenancehours * Expected number of failures = 40 * 2 = 80 hours
MLH / OH = 80/10000 =
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