C++how to solvedistance= 2.82843distance= 5.19615
nt2為代表ニ炸平面中ㄧ-1黠的類別: R1為代表三隼空間中一個點的類別.在main()函款ヤ鼾稍 res c Distance ( )函數計算二維或三維空間+-二點間的距離·本程式之輸出應 為下列: Distance2.82843 Distance 5.19615 2, 請完成Distance ()函數 .不得變更已提供的部份. idetine CRT SECURENO REnos #include <iostream> – include <math.h using nameapace std: class cPoint2 i private: double x,y: public: cPoint20x-y-0: cPoint2 (double xx, double yy)-xx:yY: double X0 t return (x):1 double YO I return (y): void X (double xx)xxx void Y (double yy)y-yy: class cPoints private: cPoint2 p2: double z: public: cPoint3 (double xx, double yy, double zz) :p2(x, w) { :-zz: } double X) return (p2.xo): double YO
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