Course Solutions Uncategorized (Solved) : Given Final Capacitance Found Example 12 9th Edition Example 11 10th Edition Ch 19 E Capac Q32456002 . . . .

(Solved) : Given Final Capacitance Found Example 12 9th Edition Example 11 10th Edition Ch 19 E Capac Q32456002 . . . .

 

Given the final capacitance found in Example 12 in the 9th edition or Example 11 in the 10th edition from Ch. 19 (i.e., the capacitance when the key is pressed) and assuming a voltage of 5V runs through the keyboard circuitry, about how many electrons must there be on the negative plate of the capacitor? (use q = 1.602 x 10-19 C for one electron, info from example 11: the separation of the plates is normally 5.00 x 104-3 m, but decreases to 0.150 x10A-3 m when a key is pressed. plate area: 9.5 x 10A-5 mA2. dielectric constant 3.5. let me know if additional info is needed. llin 18.3 million 612 million 9.8 x 10-11

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