Course Solutions Uncategorized (Solved) : Following Program C Int Main Int Argc Char Argv Int Currentfile 1 Char Stringbuffer 10 Cha Q35457260 . . . .

(Solved) : Following Program C Int Main Int Argc Char Argv Int Currentfile 1 Char Stringbuffer 10 Cha Q35457260 . . . .

 

I have the following program in C:

int main(int argc, char *argv[])
{
   int currentFile = 1;

   char stringBuffer[10];
   char fileName[35];

   char outputBuffer[75];
   char outputCode[5];
  
  
   int fd;
  

  
   if(argc > 1)
   {
       char* commandName = argv[1];
      
      
       for(int i=2;i       {
          sprintf(stringBuffer,”%d”,currentFile);
          
          strcpy(fileName,stringBuffer);
          strcat(fileName,”.out”);
          
           int status;

          close(stdout);
          close(stderr);

           fd =open(fileName,S_IRUSR | S_IWUSR | O_CREAT | O_TRUNC | O_RDWR,0666);

          dup2(fd,STDOUT_FILENO);
          dup2(fd,STDERR_FILENO);

           intreturnCode;
           intreturnStatus;

           intforkChild;
           forkChild =fork();

  
           if(forkChild ==0)
          {  
              signal(SIGINT,sighandler);
                 

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