Course Solutions Uncategorized (Solved) : Characters Name Type Assume Characters Distinctive Names Name Type Bob Jon Emmab Olivia C Q34950006 . . . .

(Solved) : Characters Name Type Assume Characters Distinctive Names Name Type Bob Jon Emmab Olivia C Q34950006 . . . .

 

Characters(name, type): assume characters have distinctive names name type Bob A Jon A EmmaB Olivia C Appearances (name, seas

Characters(name, type): assume characters have distinctive names name type Bob A Jon A EmmaB Olivia C Appearances (name, season, num) name season num Bob1 Bob 1 Jon1 Jon 2 Emma 1 Emma 1 Emma 2 Bob 2 Olivia 2 Episodes(season, num, title, viewers) season num title viewerS Winter 2.5 M King 2.5 M Notes4.0 M 2 Lands 3.2 M 2 2 Problem 2: [30 pt] Elementary SQL: write SQL queries using previous tables a)[5 pt] Find good episodes: find

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