Course Solutions Uncategorized (Solved) : 4 25pts Given String Initial X Value Fx Pselect Expected Po 1 01110 14 196 018 2 11100 28 Q29223329 . . . .

(Solved) : 4 25pts Given String Initial X Value Fx Pselect Expected Po 1 01110 14 196 018 2 11100 28 Q29223329 . . . .

 

4) (25pts) Given String Initial x value fx) pselect Expected No. Po 1 01110 14 196 0.18 2 11100 28 784 0.72 3 01010 10 100 0.096 X2 fi lsum() fi/ave) 0.72 2.88 0.384 0.016 4.00 1.00 2.88 400010 2 4 0004 sum average Max 1084 1.00 271 0.25 784 0.72 the random numbers generated for reproduction are 15, 67, 29,98, and that the random numbers generated for crossover site are 1 & 3, fill in the following table showing the next generation. gLLI Mating! Matel crossover New Pool x value |f(x) site Member 2 ret

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