Course Solutions Uncategorized (Solved) : 10 12 32 5272 92130 180 230280330 Temperature T C 153 15291528 1527 15261522 15141419 1331 Q38072703 . . . .

(Solved) : 10 12 32 5272 92130 180 230280330 Temperature T C 153 15291528 1527 15261522 15141419 1331 Q38072703 . . . .

 

)10 12 32-5272-92130 180 230280330 temperature, T (°C) 15.3 15.2915.28 15.27 15.2615.22 15.1414.19 13.3112.9 knots index, i d

)10 12 32-5272-92130 180 230280330 temperature, T (°C) 15.3 15.2915.28 15.27 15.2615.22 15.1414.19 13.3112.9 knots index, i depth, z (m) 3 6i Table 1: Temperature of seawater in the upper layer of the ocean. Problem 1 (hand-calculation): Consider the seawater temperature data in table 1 to estimate the temperature at depth z –150 m. Use natural cubic splines to find the piecewise cubic polynomials that pass through the knots 5 through 8. You can use MATLAB to solve the

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