Course Solutions Uncategorized (Answered) : A given project’s critical path has an expected duration of 63 days, with a standard deviation of 2 days. What is the probabilit

(Answered) : A given project’s critical path has an expected duration of 63 days, with a standard deviation of 2 days. What is the probabilit

A given project’s critical path has an expected duration of 63 days, with a standard deviation of 2 days. What is the probability that this project will take longer than 63.1 days?

Expert Answer


μ = expected duration (mean) = 63
σ = standard deviation = 2

Let X ~ Normal(63, 2) be the random variable representing the project duration. We need to find Probability of X being more than 63.1 days.

P(X > 63.1) = 1 – P(X < 63.1) = 1 - P((X - μ) / σ < (63.1 - μ) / σ) We know that the standard normal variable Z

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