Course Solutions Uncategorized (Solved) : 32 Pages User Space Virtual Storage Page 1k Bytes Size Computer 16k Bytes Main Memory 1 Ma Q29918631 . . . .

(Solved) : 32 Pages User Space Virtual Storage Page 1k Bytes Size Computer 16k Bytes Main Memory 1 Ma Q29918631 . . . .

 

There are 32 pages in the user space of virtual storage. Each page is 1K bytes size. And the computer has 16K bytes main memory. (1) How many bits are needed to describe logical address space?* (2) How many bits are needed to describe physical address space?* (3) Assume one instance that the page 0, 1, 2, 3 was respectively loaded into 1. frame page 5, 10, 4, 7, please calculate the physical address of the logical address 2,652 and 1,340(Decimal).

There are 32 pages in the user space of virtual storage. Each page is 1K bytes

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