<p>Given a,b,c</p><p>a,b,c in the domain of all positive integers, in a proof to thetheorem a3+b3+c3≥a2b+b2c+c2aa3+b3+c3≥a2b+b2c+c2a, we may assumewithout loss of generality that:<br/><strong>A.</strong> a≥b,a≥ca≥b,a≥c<br/><strong>B.</strong> a≥b,b≥ca≥b,b≥c<br/><strong>C.</strong> a≥c,c≥ba≥c,c≥b<br/><strong>D.</strong> a≥c,b≥c</p> Expert Answer Answer