Course Solutions Uncategorized (Solved) : Fibonacci Function Easy Define Recursively Done Naively Inefficient Re Computing Fibonacci Q26446992 . . . .

(Solved) : Fibonacci Function Easy Define Recursively Done Naively Inefficient Re Computing Fibonacci Q26446992 . . . .

 

A Fibonacci function is easy to define recursively, but done naively it is inefficient, re-computing the same Fibonacci value many times as it recursively descends down both recursive calls. For example, given a definition, def fib(n: Int ) : Int = { if (n<2) 1 else fib(n-1)+fib (n-2) } calling fib (5) ends up computing fib (3) twice, fib (2) thrice, and the base case of fib (1) or fib (0) 8 times during the course of its recursive unfolding. Come up with a more efficient version, fib2 (with the same type signature) that only ever computes a given Fibonacci number once. Note that you can time your code to observe the difference. For this you can use, import System.nanoTime def profile [R] (code: => R, t: Long = nanoTime) = (code, nanoTime - t)please

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