Course Solutions Uncategorized (Solved) : P1 Z 65 2 10pt Strings Implement Void Split Str Char S Char Pk Char Pv Takes String S Form Q30623894 . . . .

(Solved) : P1 Z 65 2 10pt Strings Implement Void Split Str Char S Char Pk Char Pv Takes String S Form Q30623894 . . . .

 

p1->z = 65 2. (10pt) /Strings] Implement void split str (char *s, char **pk, char **pv) which takes a string s in the form of key:value and dynamically creat strings key and value whose references will be returned through pk an string s does not contain : pk and pv d pv.I or memory allocations fail, make sure you return NULL through For example, after char *k, v; split str (abcd: klm, &k,& v) k points to abcd and v points to klm After char *k, v split str (myKeymyValue, &k, &v) k is NULL and vis NULL /* give your solution to this problem in the next page /

p1->z

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