Course Solutions Uncategorized (Answered) : Predecessor Activity M 9 12 9 24 C 8 1216 5 6 10 C E 712 D G H J 9 20 C E Expected Estimat Q34402639

(Answered) : Predecessor Activity M 9 12 9 24 C 8 1216 5 6 10 C E 712 D G H J 9 20 C E Expected Estimat Q34402639

June 27, 2024June 27, 2024| adminadmin| 0 Comment| 6:57 pm
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and predecessor Activity a m 9 12 9 24 C 8 1216 5 6 10 C, E 712 D, G, H I, J 9 20 C, E a) The expected (estimated) time for activity C is 12 weeks. (Round your response to two decimal places) b) The variance for activity C is 1.78 weeks. (Round your response to two decimal places) o) Based on the calculation of the estimated times, the critical path is A-B-E-F.H.J-K d) The estimated time for the oritical path is 42.83 weeks. (Round your response to two decimal places.) e) The activity variance along the critical path is 24.75 weeks. (Round your response io two decimal places) 1) The probability that Hopkins Hospitality will fnish the project in 40 weeks or less is .(Enter as a probability and round your response to three decimal places)and

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